Sort elements in a list - Python
Sort list item as per the order in another list
I need to sort elements in a
as per the order in b
.
a = ['S', 'XXL', 'M', 'L' ]
b = ['XS','S','M','L','XL','XXL']
a.sort(key=lambda (x): b.index(x))
print a
>>>['S', 'M', 'L', 'XXL']
Sort in asending order
K = ['22', '40', '70', '10']
K = sorted(K)
print K
>>>['10', '22', '40', '70']
Sort in desending order
K = ['22', '40', '70', '10']
K = sorted(K, reverse=True)
print K
>>>['70', '40', '22', '10']
Recent Posts
- Solve "ValueError invalid literal for int() with base 10" - Python
- Handling dynamic subdomain with Flask - Python
- A minimal example about WordPress object cache
- Select random element from a list - Python
- Write our first Selenium program with Python 3 & Firefox
Your Questions / Comments
If you found this article interesting, found errors, or just want to discuss about it, please get in touch.